Java DatagramSocket .receive (DatagramPacket p)

Syntax

DatagramSocket.receive(DatagramPacket p) has the following syntax.

public void receive(DatagramPacket p)  throws IOException

Example

In the following code shows how to use DatagramSocket.receive(DatagramPacket p) method.


//ww w.j a  v  a  2  s  .  co  m
import java.net.DatagramPacket;
import java.net.DatagramSocket;

public class Main {
  private final static int BUFSIZE = 20;

  public static void main(String args[]) {
    try {
      int port = 80;

      DatagramSocket ds = new DatagramSocket(port);

      while (true) {
        byte buffer[] = new byte[BUFSIZE];

        DatagramPacket dp = new DatagramPacket(buffer, buffer.length);

        ds.receive(dp);

        String str = new String(dp.getData());

        System.out.println(str);
      }
    } catch (Exception e) {
      e.printStackTrace();
    }
  }
}




















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