Java DatagramSocket .receive (DatagramPacket p)
Syntax
DatagramSocket.receive(DatagramPacket p) has the following syntax.
public void receive(DatagramPacket p) throws IOException
Example
In the following code shows how to use DatagramSocket.receive(DatagramPacket p) method.
//ww w.j a v a 2 s . co m
import java.net.DatagramPacket;
import java.net.DatagramSocket;
public class Main {
private final static int BUFSIZE = 20;
public static void main(String args[]) {
try {
int port = 80;
DatagramSocket ds = new DatagramSocket(port);
while (true) {
byte buffer[] = new byte[BUFSIZE];
DatagramPacket dp = new DatagramPacket(buffer, buffer.length);
ds.receive(dp);
String str = new String(dp.getData());
System.out.println(str);
}
} catch (Exception e) {
e.printStackTrace();
}
}
}