Java Files.createFile(Path path, FileAttribute <?>... attrs)
Syntax
Files.createFile(Path path, FileAttribute <?>... attrs) has the following syntax.
public static Path createFile(Path path, FileAttribute <?>... attrs) throws IOException
Example
In the following code shows how to use Files.createFile(Path path, FileAttribute <?>... attrs) method.
import java.io.IOException;
import java.nio.file.FileAlreadyExistsException;
import java.nio.file.FileSystems;
import java.nio.file.Files;
import java.nio.file.Path;
import java.nio.file.attribute.FileAttribute;
import java.nio.file.attribute.PosixFilePermission;
import java.nio.file.attribute.PosixFilePermissions;
import java.util.Set;
// ww w.ja v a2s . c o m
public class Main {
public static void main(String[] args) {
Path newfile_2 = FileSystems.getDefault().getPath("/home/tutorial/Java/2010/demo.txt");
//create a file with a set of specified attributes
Set<PosixFilePermission> perms = PosixFilePermissions.fromString("rw-------");
FileAttribute<Set<PosixFilePermission>> attr = PosixFilePermissions.asFileAttribute(perms);
try {
Files.createFile(newfile_2, attr);
} catch (IOException e) {
System.err.println(e);
}
}
}
The code above generates the following result.
