Android Long Bit Set pop_intersect(long A[], long B[], int wordOffset, int numWords)

Here you can find the source of pop_intersect(long A[], long B[], int wordOffset, int numWords)

Description

Returns the popcount or cardinality of the two sets after an intersection.

License

Apache License

Declaration

public static long pop_intersect(long A[], long B[], int wordOffset,
        int numWords) 

Method Source Code

//package com.java2s;
/**//ww  w  . j  ava2 s .c  om
 * Licensed to the Apache Software Foundation (ASF) under one or more
 * contributor license agreements.  See the NOTICE file distributed with
 * this work for additional information regarding copyright ownership.
 * The ASF licenses this file to You under the Apache License, Version 2.0
 * (the "License"); you may not use this file except in compliance with
 * the License.  You may obtain a copy of the License at
 *
 *     http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

public class Main {
    /** Returns the popcount or cardinality of the two sets after an intersection.
     * Neither array is modified.
     */
    public static long pop_intersect(long A[], long B[], int wordOffset,
            int numWords) {
        // generated from pop_array via sed 's/A\[\([^]]*\)\]/\(A[\1] \& B[\1]\)/g'
        int n = wordOffset + numWords;
        long tot = 0, tot8 = 0;
        long ones = 0, twos = 0, fours = 0;

        int i;
        for (i = wordOffset; i <= n - 8; i += 8) {
            long twosA, twosB, foursA, foursB, eights;

            // CSA(twosA, ones, ones, (A[i] & B[i]), (A[i+1] & B[i+1]))
            {
                long b = (A[i] & B[i]), c = (A[i + 1] & B[i + 1]);
                long u = ones ^ b;
                twosA = (ones & b) | (u & c);
                ones = u ^ c;
            }
            // CSA(twosB, ones, ones, (A[i+2] & B[i+2]), (A[i+3] & B[i+3]))
            {
                long b = (A[i + 2] & B[i + 2]), c = (A[i + 3] & B[i + 3]);
                long u = ones ^ b;
                twosB = (ones & b) | (u & c);
                ones = u ^ c;
            }
            //CSA(foursA, twos, twos, twosA, twosB)
            {
                long u = twos ^ twosA;
                foursA = (twos & twosA) | (u & twosB);
                twos = u ^ twosB;
            }
            //CSA(twosA, ones, ones, (A[i+4] & B[i+4]), (A[i+5] & B[i+5]))
            {
                long b = (A[i + 4] & B[i + 4]), c = (A[i + 5] & B[i + 5]);
                long u = ones ^ b;
                twosA = (ones & b) | (u & c);
                ones = u ^ c;
            }
            // CSA(twosB, ones, ones, (A[i+6] & B[i+6]), (A[i+7] & B[i+7]))
            {
                long b = (A[i + 6] & B[i + 6]), c = (A[i + 7] & B[i + 7]);
                long u = ones ^ b;
                twosB = (ones & b) | (u & c);
                ones = u ^ c;
            }
            //CSA(foursB, twos, twos, twosA, twosB)
            {
                long u = twos ^ twosA;
                foursB = (twos & twosA) | (u & twosB);
                twos = u ^ twosB;
            }

            //CSA(eights, fours, fours, foursA, foursB)
            {
                long u = fours ^ foursA;
                eights = (fours & foursA) | (u & foursB);
                fours = u ^ foursB;
            }
            tot8 += pop(eights);
        }

        if (i <= n - 4) {
            long twosA, twosB, foursA, eights;
            {
                long b = (A[i] & B[i]), c = (A[i + 1] & B[i + 1]);
                long u = ones ^ b;
                twosA = (ones & b) | (u & c);
                ones = u ^ c;
            }
            {
                long b = (A[i + 2] & B[i + 2]), c = (A[i + 3] & B[i + 3]);
                long u = ones ^ b;
                twosB = (ones & b) | (u & c);
                ones = u ^ c;
            }
            {
                long u = twos ^ twosA;
                foursA = (twos & twosA) | (u & twosB);
                twos = u ^ twosB;
            }
            eights = fours & foursA;
            fours = fours ^ foursA;

            tot8 += pop(eights);
            i += 4;
        }

        if (i <= n - 2) {
            long b = (A[i] & B[i]), c = (A[i + 1] & B[i + 1]);
            long u = ones ^ b;
            long twosA = (ones & b) | (u & c);
            ones = u ^ c;

            long foursA = twos & twosA;
            twos = twos ^ twosA;

            long eights = fours & foursA;
            fours = fours ^ foursA;

            tot8 += pop(eights);
            i += 2;
        }

        if (i < n) {
            tot += pop((A[i] & B[i]));
        }

        tot += (pop(fours) << 2) + (pop(twos) << 1) + pop(ones)
                + (tot8 << 3);

        return tot;
    }

    /** Returns the number of bits set in the long */
    public static int pop(long x) {
        /* Hacker's Delight 32 bit pop function:
         * http://www.hackersdelight.org/HDcode/newCode/pop_arrayHS.cc
         *
        int pop(unsigned x) {
           x = x - ((x >> 1) & 0x55555555);
           x = (x & 0x33333333) + ((x >> 2) & 0x33333333);
           x = (x + (x >> 4)) & 0x0F0F0F0F;
           x = x + (x >> 8);
           x = x + (x >> 16);
           return x & 0x0000003F;
          }
         ***/

        // 64 bit java version of the C function from above
        x = x - ((x >>> 1) & 0x5555555555555555L);
        x = (x & 0x3333333333333333L) + ((x >>> 2) & 0x3333333333333333L);
        x = (x + (x >>> 4)) & 0x0F0F0F0F0F0F0F0FL;
        x = x + (x >>> 8);
        x = x + (x >>> 16);
        x = x + (x >>> 32);
        return ((int) x) & 0x7F;
    }
}

Related

  1. nextHighestPowerOfTwo(long v)
  2. pop_andnot(long A[], long B[], int wordOffset, int numWords)
  3. pop_array(long A[], int wordOffset, int numWords)
  4. pop_union(long A[], long B[], int wordOffset, int numWords)
  5. pop_xor(long A[], long B[], int wordOffset, int numWords)
  6. swapBytes(long value)