Android URL String Validate isUrl(String s)

Description

is Url

License

Apache License

Parameter

Parameter	Description
s	a parameter

Declaration

public static boolean isUrl(String s) 

Method Source Code

//package com.java2s;
/**// w ww .java 2  s  . com
 * Copyright (c) 2013-2014, Rinc Liu (http://rincliu.com).
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *      http://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

import java.util.regex.Pattern;

public class Main {
    private static final String URL_REG_EXPRESSION = "^(https?://)?([a-zA-Z0-9_-]+\\.[a-zA-Z0-9_-]+)+(/*[A-Za-z0-9/\\-_&:?\\+=//.%]*)*";

    /**
     * @param s
     * @return
     */
    public static boolean isUrl(String s) {
        if (s == null) {
            return false;
        }
        return Pattern.matches(URL_REG_EXPRESSION, s);
    }
}

Related

1. isValidUrl(String linkToCheck)