Android XPath Evaluate asNode(String nodeName, Node node)

Description

as Node

License

Open Source License

Declaration

public static Node asNode(String nodeName, Node node)
            throws XPathExpressionException 

Method Source Code

//package com.java2s;
/*/*from   w ww.  j a  va  2s.c om*/
 * Copyright 2010-2013 Amazon.com, Inc. or its affiliates. All Rights Reserved.
 *
 * Licensed under the Apache License, Version 2.0 (the "License").
 * You may not use this file except in compliance with the License.
 * A copy of the License is located at
 *
 *  http://aws.amazon.com/apache2.0
 *
 * or in the "license" file accompanying this file. This file is distributed
 * on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either
 * express or implied. See the License for the specific language governing
 * permissions and limitations under the License.
 */

import javax.xml.xpath.XPathExpressionException;

import org.w3c.dom.Node;
import org.w3c.dom.NodeList;

public class Main {
    public static Node asNode(String nodeName, Node node)
            throws XPathExpressionException {
        if (node == null)
            return null;
        return findXPathNode(node, nodeName);
    }

    private static Node findXPathNode(Node node, String xPath) {
        int currentSearchIndex = 0;
        while (currentSearchIndex < xPath.length()) {

            int endingIndex = xPath.indexOf("/", currentSearchIndex);

            String noderNameFromXPath = null;
            if (endingIndex == -1) {
                noderNameFromXPath = xPath.substring(currentSearchIndex);
            } else {
                noderNameFromXPath = xPath.substring(currentSearchIndex,
                        endingIndex);
            }

            node = findChildNodeWithName(node, noderNameFromXPath);

            if (endingIndex == -1) {
                break;
            }

            currentSearchIndex = endingIndex + 1;
        }

        return node;
    }

    private static Node findChildNodeWithName(Node node, String childName) {
        if (node == null) {
            return null;
        } else {
            if (node.getNodeName().equals(childName)) {
                return node;
            } else {
                NodeList nodeList = node.getChildNodes();
                for (int i = 0; i < nodeList.getLength(); i++) {
                    if (nodeList.item(i).getNodeName().equals(childName)) {
                        return nodeList.item(i);
                    }
                }

                return null;
            }
        }
    }
}

Related

1. asString(String expression, Node node)
2. asNodeList(String nodeName, Node node)
3. asLong(String expression, Node node)
4. asInteger(String expression, Node node)
5. asFloat(String expression, Node node)