Given two points, return the point at which this line will cross the given y-intercept on a 2D coordinate system. - Android Graphics

Android examples for Graphics:Path Point

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Description

Given two points, return the point at which this line will cross the given y-intercept on a 2D coordinate system.

Demo Code

/*/*from www .j  a  v  a 2  s  .  c o m*/
 * The MIT License (MIT)
 *
 * Copyright (c) 2015 ustwo studio inc (www.ustwo.com)
 *
 * Permission is hereby granted, free of charge, to any person obtaining a copy
 * of this software and associated documentation files (the "Software"), to deal
 * in the Software without restriction, including without limitation the rights
 * to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
 * copies of the Software, and to permit persons to whom the Software is
 * furnished to do so, subject to the following conditions:
 *
 * The above copyright notice and this permission notice shall be included in all
 * copies or substantial portions of the Software.
 *
 * THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
 * IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
 * FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
 * AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
 * LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
 * OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
 * SOFTWARE.
 */
//package com.java2s;
import android.graphics.PointF;

public class Main {
    /**
     * Given two points, return the point at which this line will cross the given y-intercept
     * on a 2D coordinate system.
     *
     * @param linePoint1    First point on line
     * @param linePoint2    Second point on line
     * @param y             Y-intercept
     * @return              New point where line crosses y
     */
    public static PointF getLineIntersectionWithY(PointF linePoint1,
            PointF linePoint2, float y) {
        if ((linePoint2.y == linePoint1.y)) {
            return null;
        } else {
            float x = 0;
            if (linePoint2.x != linePoint1.x) {
                float m = (linePoint2.y - linePoint1.y)
                        / (linePoint2.x - linePoint1.x);
                x = ((y - linePoint1.y) / m) + linePoint1.x;
            } else {
                x = linePoint2.x;
            }
            return new PointF(x, y);
        }
    }
}

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