Loops through 10 numbers and tests for odd and prints the even message - C Statement

Description

Loops through 10 numbers and tests for odd and prints the even message

Demo Code

#include <stdio.h>

int main()/*from w w  w  .jav a 2  s .com*/
{
    for (int i = 1; i <= 10; i++){
        if ((i%2) == 1) // Odd numbers have a remainder of 1
        {
            printf("odd\n");
            continue;
        }
        printf("Even!\n");
    }

    return 0;
}

Result

• Previous
• Next

Related Tutorials

• Use if statement to check user answer to the old yes-or-no question, case insensitive.
• Use if statement to check user answer to the old yes-or-no question, case sensitive.
• Calculates how old they will be in the current year using if statement
• Implement the sign function.
• Determine if a year is a leap year.