Check if a character is contained in a string - C String

C examples for String:String Function

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Description

Check if a character is contained in a string

Demo Code

#include <stdio.h>

#define LIMIT 50// w w  w . j a va2s . co m

int is_within(char ch, const char *string);

char * get(char *string, int n);

int main(void){
  char string[LIMIT];
  char ch;

  printf("Enter a string to search: ");
  get(string, LIMIT);
  
  while (string[0] != '\0'){
    printf("Enter a character to search for: ");
    ch = getchar();

    if (ch != '\n')
      while (getchar() != '\n')
        continue;

    char *contains = is_within(ch, string) ? "" : " not";

    printf("\"%s\" does%s contain %c\n", string, contains, ch);

    printf("Enter a string to search (empty line to quit): ");
    get(string, LIMIT);
  }
  puts("Bye");

  return 0;
}
// returns 1 if char ch is in string returns 0 otherwise
int is_within(char ch, const char *string){
  while(*string != '\0'){
    if (*string == ch)
      return 1;
    string++;
  }
  return 0;
}
// wrapper for fgets that replaces first newline with null
char * get(char *string, int n){
  char *return_value = fgets(string, n, stdin);
  while (*string != '\0'){
    if (*string == '\n'){
      *string = '\0';
      break;
    }
    string++;
  }
  return return_value;
}

Result


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