Sorts person objects using array of pointers - C++ Class

C++ examples for Class:Class Pointer

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Description

Sorts person objects using array of pointers

Demo Code

#include <iostream>
#include <string>
using namespace std;
class person//from ww  w .  j  a  va2s. c om
{
   protected:
   string name;
   public:
   void setName()
   { cout << "Enter name: "; cin >> name; }
   void printName()
   { cout << endl << name; }
   string getName()
   { return name; }
};
void bsort(person**, int);
int main()
{
   person* persPtr[100];
   int n = 0;                     //number of persons in array
   char choice;                   //input char
   do {                           //put persons in array
       persPtr[n] = new person;    //make new object
       persPtr[n]->setName();      //set person's name
       n++;                        //count new person
       cout << "Enter another (y/n)? "; //enter another
       cin >> choice;              //   person?
    }
    while( choice=='y' );          //quit on 'n'
    cout << "\nUnsorted list:";
    for(int j=0; j<n; j++)
    {
       persPtr[j]->printName();
    }
    bsort(persPtr, n);             //sort pointers
    cout << "\nSorted list:";
    for(int j=0; j<n; j++)
    {
       persPtr[j]->printName();
    }
    cout << endl;
    return 0;
}
void bsort(person** pp, int n)    //sort pointers to persons
{
    void order(person**, person**);  //prototype
    int j, k;                      //indexes to array
    for(j=0; j<n-1; j++)           //outer loop
       for(k=j+1; k<n; k++)        //inner loop starts at outer
    order(pp+j, pp+k);       //order the pointer contents
}
void order(person** pp1, person** pp2)  //orders two pointers
{                              //if 1st larger than 2nd,
    if( (*pp1)->getName() > (*pp2)->getName() )
    {
        person* tempptr = *pp1;     //swap the pointers
        *pp1 = *pp2;
        *pp2 = tempptr;
    }
}

Result


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