Append two linked list objects of characters.

Description

Demo Code

#include <iostream>

template <typename NODETYPE>
class List;//from  w  w  w.  j  av a2 s .  c  o m

template <typename NODETYPE>
class ListNode {
    friend class List<NODETYPE>;  // make List a friend

 public:
    explicit ListNode(const NODETYPE &);

    NODETYPE getData() const;

 private:
    NODETYPE data;
    ListNode<NODETYPE> *nextPtr;
};

template <typename NODETYPE>
ListNode<NODETYPE>::ListNode(const NODETYPE &info) : data(info), nextPtr(0) {}

template <typename NODETYPE>
NODETYPE ListNode<NODETYPE>::getData() const {
    return data;
}

template <typename NODETYPE>
class List {
 public:
    List();
    ~List();

    void insertAtFront(const NODETYPE &);
    void insertAtBack(const NODETYPE &);
    bool removeFromFront(NODETYPE &);
    bool removeFromBack(NODETYPE &);
    void concatenate(List<NODETYPE> &);
    bool isEmpty() const;
    void print() const;
    int size() const;

 private:
    ListNode<NODETYPE> *firstPtr;  // pointer to first node
    ListNode<NODETYPE> *lastPtr;   // pointer to last node

    int sz;

    ListNode<NODETYPE> *getNewNode(const NODETYPE &);
};

template <typename NODETYPE>
List<NODETYPE>::List() : firstPtr(0), lastPtr(0), sz(0) {}

template <typename NODETYPE>
List<NODETYPE>::~List() {
    if (!isEmpty()) {
        ListNode<NODETYPE> *currentPtr = firstPtr;

        while (currentPtr != 0) {
            ListNode<NODETYPE> *tempPtr = currentPtr;
            currentPtr = currentPtr->nextPtr;
            delete tempPtr;
        }
    }
}

template <typename NODETYPE>
void List<NODETYPE>::insertAtFront(const NODETYPE &value) {
    ListNode<NODETYPE> *newPtr = getNewNode(value);

    if (isEmpty()) {
        firstPtr = lastPtr = newPtr;  // new list only has one node
    } else {
        newPtr->nextPtr = firstPtr;  // point new node to previous list node
        firstPtr = newPtr;
    }
    ++sz;
}

template <typename NODETYPE>
void List<NODETYPE>::insertAtBack(const NODETYPE &value) {
    ListNode<NODETYPE> *newPtr = getNewNode(value);

    if (isEmpty()) {
        firstPtr = lastPtr = newPtr;  // new list has only one node
    } else {
        lastPtr->nextPtr = newPtr;
        lastPtr = newPtr;
    }
    ++sz;
}

template <typename NODETYPE>
bool List<NODETYPE>::removeFromFront(NODETYPE &value) {
    if (isEmpty()) {  // list is empty
        return false;
    } else {
        ListNode<NODETYPE> *tempPtr = firstPtr;

        if (firstPtr == lastPtr)
            firstPtr = lastPtr = 0;  // no nodes remain after removal
        else
            firstPtr = firstPtr->nextPtr;  // point to previous 2nd node

        value = tempPtr->data;
        delete tempPtr;

        --sz;

        return true;
    }
}

template <typename NODETYPE>
bool List<NODETYPE>::removeFromBack(NODETYPE &value) {
    if (isEmpty()) {  // list is empty
        return false;
    } else {
        ListNode<NODETYPE> *tempPtr = lastPtr;

        if (firstPtr == lastPtr) {   // list has one element
            firstPtr = lastPtr = 0;  // no nodes remain after removal
        } else {
            ListNode<NODETYPE> *currentPtr = firstPtr;

            // locate second to last element
            while (currentPtr->nextPtr != lastPtr)
                currentPtr = currentPtr->nextPtr;  // move to next node

            lastPtr = currentPtr;     // remove last node
            currentPtr->nextPtr = 0;  // this is now the last node
        }

        value = tempPtr->data;
        delete tempPtr;

        --sz;
        return true;
    }
}

template <typename NODETYPE>
void List<NODETYPE>::concatenate(List<NODETYPE> &listSecond) {
    ListNode<NODETYPE> *currentPtr = listSecond.firstPtr;

    while (currentPtr != 0) {
        insertAtBack(currentPtr->getData());
        currentPtr = currentPtr->nextPtr;
    }
}

template <typename NODETYPE>
bool List<NODETYPE>::isEmpty() const {
    return firstPtr == 0;
}

template <typename NODETYPE>
ListNode<NODETYPE> *List<NODETYPE>::getNewNode(const NODETYPE &value) {
    return new ListNode<NODETYPE>(value);
}

template <typename NODETYPE>
void List<NODETYPE>::print() const {
    if (isEmpty()) {
        std::cout << "The list is empty\n\n";
        return;
    }

    ListNode<NODETYPE> *currentPtr = firstPtr;

    while (currentPtr != 0) {
        std::cout << currentPtr->getData() << ' ';
        currentPtr = currentPtr->nextPtr;
    }
}

template <typename NODETYPE>
int List<NODETYPE>::size() const {
    return sz;
}

#include <iostream>

int main(int argc, const char* argv[]) {
    List<char> charList1;
    List<char> charList2;

    for (char c = 'a'; c <= 'z'; ++c) {
        if (c < 'n')
            charList1.insertAtBack(c);
        else
            charList2.insertAtBack(c);
    }

    std::cout << "List 1 : ";
    charList1.print();
    std::cout << "size : " << charList1.size() << "\nList 2 : ";
    charList2.print();
    std::cout << "size : " << charList2.size() << std::endl;

    charList1.concatenate(charList2);

    std::cout << "List 1 after concatenate: ";
    charList1.print();
    std::cout << " size : " << charList1.size() << std::endl;

    return 0;
}
Append two linked list objects of characters. - C++ Data Structure

Description

Demo Code

Result

Related Tutorials
