Pass a pointer into a function to modify the variable outside functions - C++ Function

Description

Pass a pointer into a function to modify the variable outside functions

Demo Code

#include <iostream>
using namespace std;
void f(int* p) {
   cout << "p = " << p << endl;
   cout << "*p = " << *p << endl;
   *p = 5;//from   ww  w  . ja v  a2s  .com
   cout << "p = " << p << endl;
}
int main() {
   int x = 47;
   cout << "x = " << x << endl;
   cout << "&x = " << &x << endl;
   f(&x);
   cout << "x = " << x << endl;
}

Result

• Previous
• Next

Related Tutorials

• Demonstrate function overloading
• Demonstrate overloaded functions
• When you pass an argument to a function, a copy of that argument is made inside the function.
• Pass structure reference to a function
• Passing a Structure to a Function