Continue to accumulate the sum of these numbers until the user enters a 0. - C++ Statement

Description

Continue to accumulate the sum of these numbers until the user enters a 0.

Demo Code

#include <cstdio>
#include <cstdlib>
#include <iostream>
using namespace std;

int main(int nNumberofArgs, char* pszArgs[])
{
    cout << "Terminate the series by entering two\n negative numbers in a row\n";

    int accumulator;
    for(;;)// ww w. j a v a  2  s. c  o  m
    {
        accumulator = 0;
        cout << "Start the next sequence\n";
        for(;;){
            int nValue = 0;
            cout << "Enter next number: ";
            cin  >> nValue;

            if (nValue < 0){
                break;
            }
            accumulator += nValue;
        }
        if (accumulator == 0)
        {
            break;
        }
        cout << "The total for this sequence is " << accumulator << endl << endl;
    }
    return 0;
}

Result

• Previous
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Related Tutorials

• Simple menu program demonstrating the use of break and continue
• Loop with both the continue and break statements.
• Continue to accumulate the sum of these numbers until the user enters a negative number.
• Use functions to break the inner loop into its own function
• Break appears after an if statement. A conditional break, which occurs only if the relational test of the if statement is True.