Determine if one vector is less than vector with lexicographical compare. - C++ STL

C++ examples for STL:vector

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Description

Determine if one vector is less than vector with lexicographical compare.

Demo Code

#include <iostream>
#include <vector>
using namespace std;
void show(const char *msg, vector<char> vect);
int main() {//from  ww w .  j a  va  2  s . c o m
   // Declare an empty vector that can hold char objects.
   vector<char> v;
   // Declare an iterator to a vector<char>.
   vector<char>::iterator itr;
   // Obtain an iterator to the start of v.
   itr = v.begin();
   // Declare a reverse iterator.
   vector<char>::reverse_iterator ritr;
   // Create another vector that is the same as the first.
   vector<char> v2(v);
   show("The contents of v2: ",v2);
   cout << "\n";
   // Insert more characters into v and v2 at the end.
   cout << "Insert more characters into v and v2.\n";
   v.insert(v.end(), 'D');
   v.insert(v.end(), 'E');
   v2.insert(v2.end(), 'X');
   if(v < v2)
      cout << "v is less than v2.\n\n";
   return 0;
}
void show(const char *msg, vector<char> vect) {
   vector<char>::iterator itr;
   cout << msg;
   for(itr=vect.begin(); itr != vect.end(); ++itr)
      cout << *itr << " ";
   cout << "\n";
}

Result


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