Replacing Characters in a string, erase and replace - C++ STL

C++ examples for STL:string

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Description

Replacing Characters in a string, erase and replace

Demo Code

#include <iostream>
#include <string>

int main(int argc, const char* argv[]) {
    // compiler concatenates all parts into one string
    std::string string1(//from   ww  w  .j  a v a 2  s .c om
        "qqqqqqqqqqqqqq"
        "\ntest test test test test"
        "\nthis is a test"
        "\nthis is another test"
        "\nstring test string test");

    std::cout << "Original string is:\n" << string1 << std::endl << std::endl;

    // remove all characters from (and including) location 62
    // through the end of string1
    string1.erase(62);

    // output new string
    std::cout << "Original string after erase:\n" << string1 << "\n\nAfter first replacement:\n";

    unsigned int position = string1.find(" ");

    // replace all spaces with periods
    while (position != std::string::npos) {
        string1.replace(position, 1, ".");
        position = string1.find(" ", position + 1);
    }

    std::cout << string1 << "\n\nAfter second replacement:\n";

    position = string1.find(".");  // find first period

    // replace all period with two semicolons
    while (position != std::string::npos) {
        string1.replace(position, 2, "xxxxx;;yyy", 5, 2);
        position = string1.find(".", position + 1);
    }

    std::cout << string1 << std::endl;

    return 0;
}

Result


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