CSharp - LINQ XML DescendantNodes


The DescendantNodes operator can be called on a sequence of elements and returns a sequence containing the descendant nodes of each element or document.


public static IEnumerable<XNode> DescendantNodes<T> (
        this IEnumerable<T> source
      ) where T : XContainer

The following example will build a XML tree.

Then call the DescendantNodes operator.


using System;
using System.Linq;
using System.Xml.Linq;
using System.Collections.Generic;

class Program/*from   ww  w . j  av  a  2  s.c  o  m*/
    static void Main(string[] args){
        XDocument xDocument = new XDocument(
          new XElement("Books",
            new XElement("Book",
              new XAttribute("type", "Author"),
              new XComment("This is a new author."),
              new XElement("FirstName", "Joe"),
              new XElement("LastName", "Ruby")),
            new XElement("Book",
              new XAttribute("type", "Editor"),
              new XElement("FirstName", "PHP"),
              new XElement("LastName", "Python"))));
        IEnumerable<XElement> elements =
        //  First, we will display the source elements.
        foreach (XElement element in elements)
          Console.WriteLine("Source element: {0} : value = {1}",
            element.Name, element.Value);
        //  Now, we will display each source element's descendant nodes.
        foreach (XNode node in elements.DescendantNodes())
          Console.WriteLine("Descendant node: {0}", node);