CSharp - LINQ XML DescendantNodesAndSelf


The DescendantNodesAndSelf operator can be called on a sequence of elements and returns a sequence containing each source element itself and each source element's descendant nodes.


public static IEnumerable<XNode> DescendantNodesAndSelf (
        this IEnumerable<XElement> source


using System;
using System.Linq;
using System.Xml.Linq;
using System.Collections.Generic;

class Program/*from  w  ww .  j a v a  2 s  .co m*/
    static void Main(string[] args){
              XDocument xDocument = new XDocument(
                new XElement("Books",
                  new XElement("Book",
                    new XAttribute("type", "Author"),
                    new XComment("This is a new author."),
              new XElement("FirstName", "Joe"),
              new XElement("LastName", "Ruby")),
            new XElement("Book",
              new XAttribute("type", "Editor"),
              new XElement("FirstName", "PHP"),
              new XElement("LastName", "Python"))));
        IEnumerable<XElement> elements =
        //  First, we will display the source elements.
        foreach (XElement element in elements)
          Console.WriteLine("Source element: {0} : value = {1}",
            element.Name, element.Value);
        //  Now, we will display each source element's descendant nodes.
        foreach (XNode node in elements.DescendantNodesAndSelf())
          Console.WriteLine("Descendant node: {0}", node);