CSharp - Write program to keep throwing a dice until there are two 6s

Requirements

You will write a program that throws a die until the 6 appears for the second time.

Hint

You simply count the 6s.

If there are two 6x, exit the while loop

Demo

using System;
class Program//from  w w w.j  av a 2 s  .  co m
{
    static void Main(string[] args)
    {
        // Random number generator 
        Random randomNumbers = new Random();

        // Throwing until the second six is thrown 
        int howManySixes = 0;
        do
        {
            // Actual throwing 
            int thrown = randomNumbers.Next(1, 6 + 1);
            Console.WriteLine(thrown);
            // Counting sixes 
            if (thrown == 6)
            {
                howManySixes++;
            }
        } while (howManySixes < 2);

    }
}

Result