Example usage for edu.stanford.nlp.util StringUtils isPunct

Introduction

In this page you can find the example usage for edu.stanford.nlp.util StringUtils isPunct.

Prototype

public static boolean isPunct(String s) 

Source Link

Document

Given a String the method uses Regex to check if the String only contains punctuation characters

Usage

From source file:knu.univ.lingvo.coref.Mention.java

License:Open Source License

public String getPattern(List<CoreLabel> pTokens) {

    ArrayList<String> phrase_string = new ArrayList<String>();
    String ne = "";
    for (CoreLabel token : pTokens) {
        if (token.index() == headWord.index()) {
            phrase_string.add(token.lemma());
            ne = "";

        } else if ((token.lemma().equals("and") || StringUtils.isPunct(token.lemma()))
                && pTokens.size() > pTokens.indexOf(token) + 1 && pTokens.indexOf(token) > 0
                && pTokens.get(pTokens.indexOf(token) + 1).ner()
                        .equals(pTokens.get(pTokens.indexOf(token) - 1).ner())) {

        } else if (token.index() == headWord.index() - 1 && token.ner().equals(nerString)) {
            phrase_string.add(token.lemma());
            ne = "";

        } else if (!token.ner().equals("O")) {
            if (!token.ner().equals(ne)) {
                ne = token.ner();/*from w  ww .j a va2 s.  c  o  m*/
                phrase_string.add("<" + ne + ">");
            }

        } else {
            phrase_string.add(token.lemma());
            ne = "";
        }
    }
    return StringUtils.join(phrase_string);
}

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