Java - Odd And Even Pairs

Description

List all Odd And Even Pairs in a string

The input is a string with integer values, for example, "1 2 3 4 5 6".

Your task is to check if pair is different, odd or even.

Test cases

You can use the following test cases to verify your code logics.

ID	Input	Ouput
1	1 2	different
2	2 2	Even
3 1 2 3 3 6 6 1, 2 --> different 3, 3 --> both are odd 6, 6 --> both are even
4	"1 2 3 4 6"	Invalid length (since the count is a even number, 5) (the array of input numbers is not even!)

Code template

Cut and paste the following code snippet to start solve this problem.

public class Main {
  public static void main(String[] args) {
    test("1 2");
    test("2 2");
    test("1 2 3 3 6 6");
    test("1 2 3 4 6");
  }

  public static void test(String inputStr) {
    //your code
  }
}

Answer

Here is the answer to the question above.

Demo

public class Main {
  public static void main(String[] args) {
    test("1 2");/*from  w  w  w .  ja  va  2  s .c  o m*/
    test("2 2");
    test("1 2 3 3 6 6");
    test("1 2 3 4 6");
  }

  public static void test(String inputStr) {
    String[] inputStrArr = inputStr.split(" ");
    int countNumbers = inputStrArr.length;
    if ((countNumbers % 2) == 0) {
      for (int i = 0; i < countNumbers - 1; i = i + 2) {
        int number1 = Integer.parseInt(inputStrArr[i]);
        int number2 = Integer.parseInt(inputStrArr[i + 1]);

        if (((number1 % 2) == 0) && ((number2 % 2) == 0)) {
          // both are even
          System.out.printf("%d, %d --> both are even\n", number1, number2);
        } else if (((number1 % 2) != 0) && ((number2 % 2) != 0)) {
          // both are odd
          System.out.printf("%d, %d --> both are odd\n", number1, number2);
        } else {
          System.out.printf("%d, %d --> different\n", number1, number2);
        }
      }
    } else {
      System.out.println("Invalid length");
    }
  }
}