Java tutorial
/* * Copyright (C) 2008 Google Inc. * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ package com.google.uzaygezen.core; import com.google.common.base.Preconditions; /** * @author Daniel Aioanei */ public class BitVectorMath { private BitVectorMath() { } /** * Splits the bits from {@code bs} into {@code result} by putting the * lowest bits at the end of {@code result} and so on until the highest bits * are put at the beginning of {@code result}. This is similar to the big * endian representation of numbers, only that each digit has a potentially * different size. The bit set length must be equal to {@code * sum(elementLengths)}. * * @param bs little endian bit set * @param result output */ public static void split(BitVector bs, BitVector[] result) { int sum = 0; for (BitVector bv : result) { sum += bv.size(); } Preconditions.checkArgument(sum == bs.size(), "size sum does not match"); int startIndex = 0; for (int i = result.length; --i >= 0;) { result[i].copyFromSection(bs, startIndex); startIndex += result[i].size(); } Preconditions.checkArgument(startIndex >= bs.length(), "bit length is too high"); } }