org.springframework.core.serializer.support.SerializingConverter.java Source code

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/*
 * Copyright 2002-2015 the original author or authors.
 *
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 *
 *      https://www.apache.org/licenses/LICENSE-2.0
 *
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 */

package org.springframework.core.serializer.support;

import java.io.ByteArrayOutputStream;

import org.springframework.core.convert.converter.Converter;
import org.springframework.core.serializer.DefaultSerializer;
import org.springframework.core.serializer.Serializer;
import org.springframework.util.Assert;

/**
 * A {@link Converter} that delegates to a
 * {@link org.springframework.core.serializer.Serializer}
 * to convert an object to a byte array.
 *
 * @author Gary Russell
 * @author Mark Fisher
 * @since 3.0.5
 */
public class SerializingConverter implements Converter<Object, byte[]> {

    private final Serializer<Object> serializer;

    /**
     * Create a default {@code SerializingConverter} that uses standard Java serialization.
     */
    public SerializingConverter() {
        this.serializer = new DefaultSerializer();
    }

    /**
     * Create a {@code SerializingConverter} that delegates to the provided {@link Serializer}.
     */
    public SerializingConverter(Serializer<Object> serializer) {
        Assert.notNull(serializer, "Serializer must not be null");
        this.serializer = serializer;
    }

    /**
     * Serializes the source object and returns the byte array result.
     */
    @Override
    public byte[] convert(Object source) {
        ByteArrayOutputStream byteStream = new ByteArrayOutputStream(1024);
        try {
            this.serializer.serialize(source, byteStream);
            return byteStream.toByteArray();
        } catch (Throwable ex) {
            throw new SerializationFailedException(
                    "Failed to serialize object using " + this.serializer.getClass().getSimpleName(), ex);
        }
    }

}