Java tutorial
/* * Copyright 2013 Phil Brown * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. */ package self.philbrown.javaQuery; import java.io.IOException; import org.apache.http.HttpEntity; import org.apache.http.HttpResponse; import org.apache.http.ParseException; import org.apache.http.StatusLine; import org.apache.http.client.ClientProtocolException; import org.apache.http.client.ResponseHandler; import org.apache.http.util.EntityUtils; import org.json.JSONArray; import org.json.JSONException; import org.json.JSONObject; /** * Handle an HttpResponse as a {@link JSONObject} or {@link JSONArray}. * @author Phil Brown */ public class JSONResponseHandler implements ResponseHandler<Object> { @Override public Object handleResponse(HttpResponse response) throws ClientProtocolException, IOException { StatusLine statusLine = response.getStatusLine(); if (statusLine.getStatusCode() >= 300) { Log.e("javaQuery", "HTTP Response Error " + statusLine.getStatusCode() + ":" + statusLine.getReasonPhrase()); return null; } HttpEntity entity = response.getEntity(); if (entity == null) return null; String json = null; try { json = EntityUtils.toString(entity); if (json.startsWith("{")) { return new JSONObject(json); } else { return new JSONArray(json); } } catch (ParseException e) { throw e; } catch (JSONException e) { throw new IOException("Received malformed JSON"); } } }