Create Zip File From Directory using ZipOutputStream - Java File Path IO

Java examples for File Path IO:ZipOutputStream

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Description

Create Zip File From Directory using ZipOutputStream

Demo Code


import java.io.File;
import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;
import java.util.zip.ZipEntry;
import java.util.zip.ZipOutputStream;

public class Main {

  public static void main(String args[]) {
    try {// w w  w  .  j a v a2 s  . c o m
      String zipFile = "C:/Folder/zipdemo.zip";
      String sourceDirectory = "C:/examples";

      // create byte buffer
      byte[] buffer = new byte[1024];
      FileOutputStream fout = new FileOutputStream(zipFile);

      ZipOutputStream zout = new ZipOutputStream(fout);

      File dir = new File(sourceDirectory);

      if (!dir.isDirectory()) {
        System.out.println(sourceDirectory + " is not a directory");
      } else {
        File[] files = dir.listFiles();

        for (int i = 0; i < files.length; i++) {
          System.out.println("Adding " + files[i].getName());

          // create object of FileInputStream for source file
          FileInputStream fin = new FileInputStream(files[i]);

          zout.putNextEntry(new ZipEntry(files[i].getName()));

          int length;

          while ((length = fin.read(buffer)) > 0) {
            zout.write(buffer, 0, length);
          }

          zout.closeEntry();

          // close the InputStream
          fin.close();
        }
      }

      // close the ZipOutputStream
      zout.close();

      System.out.println("Zip file has been created!");

    } catch (IOException ioe) {
      System.out.println("IOException :" + ioe);
    }

  }
}

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