Determines if two double values are equivalents according to the precision. - Java java.lang

Java examples for java.lang:double

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Description

Determines if two double values are equivalents according to the precision.

Demo Code


//package com.java2s;

public class Main {
    /**/*from   ww w.j a  v a 2 s . co  m*/
     * Precision for considering two double values equivalents
     */
    public static final double PRECISION = 1e-10;

    /**
     * Determines if two double values are equivalents according to the precision. Two values are equivalent if
     * abs(x-y) <= precision
     * @param x First double value to be compared
     * @param y Second double value to be compared
     * @return <i>true</i> if <i>abs(x-y) <= precision</i>, <i>false</i> otherwise
     */
    public static boolean equal(double x, double y) {
        return (Math.abs(x - y) <= PRECISION);
    }
}

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