is IPv4 Address by regex - Java java.util.regex

Java examples for java.util.regex:Match IP Address

Description

is IPv4 Address by regex

Demo Code

/*/*  w  w  w .  jav a  2s  .c  om*/
 * --------------------------------------------------------------------
 * Licensed to the Apache Software Foundation (ASF) under one
 * or more contributor license agreements.  See the NOTICE file
 * distributed with this work for additional information
 * regarding copyright ownership.  The ASF licenses this file
 * to you under the Apache License, Version 2.0 (the
 * "License"); you may not use this file except in compliance
 * with the License.  You may obtain a copy of the License at
 *
 *   http://www.apache.org/licenses/LICENSE-2.0
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 * Unless required by applicable law or agreed to in writing,
 * software distributed under the License is distributed on an
 * "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY
 * KIND, either express or implied.  See the License for the
 * specific language governing permissions and limitations
 * under the License.
 * --------------------------------------------------------------------
 *
 * This software consists of voluntary contributions made by many
 * individuals on behalf of the Apache Software Foundation.  For more
 * information on the Apache Software Foundation, please see
 * <http://www.apache.org/>.
 *
 */
//package com.java2s;
import java.util.regex.Pattern;

public class Main {
    public static void main(String[] argv) throws Exception {
        String input = "java2s.com";
        System.out.println(isIPv4Address(input));
    }

    private static final Pattern IPV4_PATTERN = Pattern
            .compile("^(25[0-5]|2[0-4]\\d|[0-1]?\\d?\\d)(\\.(25[0-5]|2[0-4]\\d|[0-1]?\\d?\\d)){3}$");

    public static boolean isIPv4Address(final String input) {
        return IPV4_PATTERN.matcher(input).matches();
    }
}

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