retrieve Input Stream By Path from ServletContext - Java Servlet JSP

Java examples for Servlet JSP:Servlet

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Description

retrieve Input Stream By Path from ServletContext

Demo Code

/*//from  w w  w . j a v  a2s  .  c o  m
 * Copyright 2014 astamuse company,Ltd.
 * 
 * Licensed under the Apache License, Version 2.0 (the "License");
 * you may not use this file except in compliance with the License.
 * You may obtain a copy of the License at
 * 
 *     http://www.apache.org/licenses/LICENSE-2.0
 * 
 * Unless required by applicable law or agreed to in writing, software
 * distributed under the License is distributed on an "AS IS" BASIS,
 * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
 * See the License for the specific language governing permissions and
 * limitations under the License.
 * 
 */
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStream;
import java.net.MalformedURLException;
import java.net.URL;
import java.net.URLConnection;
import javax.servlet.ServletContext;

public class Main{
    public final static InputStream retrieveInputStreamByPath(
            ServletContext servletContext, ClassLoader classLoader,
            String path) {
        if (path.startsWith("file:")) {
            try {
                return new URL(path).openStream();
            } catch (FileNotFoundException e) {
                return null;
            } catch (Exception e) {
                throw new RuntimeException(e);
            }
        } else if (path.startsWith("classpath:")) {
            String cls = path.substring("classpath:".length());
            if (cls.startsWith("/")) {
                cls = cls.substring(1);
            }
            return classLoader.getResourceAsStream(cls);
        } else {
            return servletContext.getResourceAsStream(path);
        }
    }
}

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