Returns XML element that exhibits the specified attribute, walking up the element hierarchy. - Java XML

Java examples for XML:XML Attribute

Description

Returns XML element that exhibits the specified attribute, walking up the element hierarchy.

Demo Code

/**//from  w w  w .  ja  v a 2  s. co m
 * Copyright (c) 2009 DITA2InDesign project (dita2indesign.sourceforge.net)  Licensed under the Apache License, Version 2.0 (the "License"); you may not use this file except in compliance with the License. You may obtain a copy of the License at     http://www.apache.org/licenses/LICENSE-2.0  Unless required by applicable law or agreed to in writing, software distributed under the License is distributed on an "AS IS" BASIS, WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. See the License for the specific language governing permissions and limitations under the License. 
 */
//package com.java2s;

import org.w3c.dom.Element;

import org.w3c.dom.Node;

public class Main {
    /**
     * Returns element that exhibits the specified attribute, walking up
     * the element hierarchy.
     * 
     * @param startNode The node to check first. It's ancestors will be interogated until 
     * the attribute is found or the root is reached.
     * @param attName The name of the attribute to find.
     * @return Returns the element or null if not found.
     * @throws I18nServiceError
     */
    public static Element getAttHolder(Element startNode, String attName) {
        Node attHolderNode = startNode;
        while ((attHolderNode.getNodeType() != Node.DOCUMENT_NODE)
                && (!((Element) attHolderNode).hasAttribute(attName))) {
            attHolderNode = attHolderNode.getParentNode();
        }
        if (attHolderNode.getNodeType() == Node.DOCUMENT_NODE) {
            return null;
        } else {
            return (Element) attHolderNode;
        }
    }
}

Related Tutorials