Nodejs Array Same same(obj)

Here you can find the source of same(obj)

Method Source Code

Array.prototype.same = function(obj) { // jshint ignore:line
    var i = this.length;
    while (i--) {
        if (obj.contains(this[i])) {
            // todo
        }/*from  w  ww .j a v  a2 s .c o  m*/
    }
    return false;
};

Related

  1. same()
    Array.prototype.same = function() {
        for(var i = 1; i < this.length; i++) {
            if(this[i] !== this[0])
                return false;
        return true;
    
  2. same(comparisons, unordered)
    Array.prototype.same = function(comparisons, unordered) {
        if (Object.prototype.toString.call(this) !== '[object Array]') {
            throw new TypeError("`this` must be Array, not " + typeof this);
        var arglen = arguments.length;
        if (arglen < 1) {
            throw new TypeError("`arguments` must have at least one comparison `Array`");
        var firstarg = arguments[0];
    ...
    
  3. sameElementCount(arr)
    Array.prototype.sameElementCount = function(arr) {
      var result = [], count = null;
      arr.sort();
      for (var i = 0; i < arr.length;) {
        count = 1;
        for (var j = i + 1; j < arr.length; j++) {
          if (arr[i] == arr[j]) {
            count++;
        result.push([ arr[i], count ]);
        i += count;
      return result;
    };
    
  4. same_values(arr)
    function findMissing(arr1, arr2){
      if((arr1.length) && (arr2.length) === 0){
        return 0;
      if(arr1.same_values(arr2)){
        return 0;
      for(num = 0; num < arr2.length; num++){
        if(isInArray(arr2[num], arr1) !== true) return arr2[num];
    ...