Nodejs Array Sub subsetOf(other)

Method Source Code

// Not the best implementation, because [1, 2, 1].subsetOf([1, 2, 3]) is true, but enough for what we need.
Array.prototype.subsetOf = function (other) {
   for (var i = 0; i < this.length; i += 1) {
      if (other.indexOf(this[i]) === -1)
         return false;
   }//from w w w. ja  va2 s. c  om
   return true;
};

Related

1. listsub(array, sizediff)

   Array.prototype.listsub = function (array, sizediff) {
       if (!array)
           return null;
     var match = [];
       for (var i = 0; i < this.length; i++) {
           if (this[i].contains(array, sizediff)) {
               match.push(this[i]);
       return match;
   

2. sub(a2)

   Array.prototype.sub = function(a2) {
     var l1 = this.length;
     var l2 = a2.length;
     var len = (l1 < l2 ? l1 : l2);
     var result = new Array(len);
     for (var i = 0; i < len; i++) {
       result[i] = this[i] - a2[i];
     return result;
   ...
   

3. sub(other)

   Array.prototype.sub = function(other) {
       console.assert(this.length == other.length, 'sub: len(a) != len(b)');
       var ret = new Array(this.length);
       for(var i = 0; i < ret.length; i++)
           ret[i] = this[i] - other[i];
       return ret;
   

4. subList(start, end)

   Array.prototype.subList = function(start, end){
     return this.slice(start, end);
   

5. subset(field, criterion)

   Array.prototype.subset = function (field, criterion) {
     var arr = new Array();
     for (var i=0 ; i<this.length ; i++) {
       if(this[i][field] === criterion) {
         arr.push(this[i]);
     return arr;