Nodejs String Palindrome Check isPalindrome()

Method Source Code

String.prototype.isPalindrome = function() {
  var str = this;
  var half = parseInt(str.length / 2, 10);

  for (var i = 0, last = str.length - 1; i < half; ++i) {
    if (str[i] != str[last - i]) return false;
  }/*w  w  w .ja  v a  2s  .  c om*/

  return true;
};

Related

1. palindrome()

   'use strict';
   String.prototype.palindrome = String.prototype.palindrome || function ( ) {
     if ( typeof this == 'string' ) {
       return this === this.split('').reverse().join('');
     else {
       return false;
   };
   ...
   

2. palindrome(loose)

   String.prototype.palindrome = function(loose) {
       var str = loose ? this.replace(/[^a-zA-Z0-9]+/gi, '').toLowerCase() : this;
       return str == str.split('').reverse().join('');
   

3. palindrome(str)

   function palindrome(str) {
     str = str.replace(/[^a-zA-Z0-9]+/gi, '').toLowerCase();
       return str == str.split('').reverse().join('');
   palindrome("eye");
   

4. palindrome(str)

   function palindrome(str) {
     var removeChar = str.replace(/[^A-Z0-9]/ig, "").toLowerCase();
     var checkPalindrome = removeChar.split('').reverse().join('');
      return (removeChar === checkPalindrome);
   palindrome("eye");
   

5. palindrome(str)

   String.prototype.reverse = function(){ return this.split("").reverse().join(""); }
   function palindrome(str) { return str == str.reverse(); }
   console.log(palindrome("ingirumimusnocteetconsumimurigni"));
   

6. isPalindrome()

   String.prototype.isPalindrome=function(){
     var palavra=this;
     for(var i=0;i<palavra.length/2;i++){
       if(palavra[i]!=palavra[palavra.length-1-i]){
         return false;
     return true;
   

7. isPalindrome()

   String.prototype.isPalindrome = function() {
     var val = this.toString().toLowerCase();
     var reverse = val.split('').reverse().join('');
     return val === reverse;
   var str = 'something';
   var result = str.isPalindrome();  
   var str2 = 'level';
   var result2 = str2.isPalindrome();  
   ...
   

8. isPalindrome()

   'use strict';
   String.prototype.isPalindrome = String.prototype.isPalindrome || function () {
     let length = Math.floor(this.length / 2);
     for (let i = 0; i < length; i++) {
       if (this[i] !== this[this.length - i - 1]) {
         return false;
     return true;
   ...
   

9. isPalindrome()

   String.prototype.isPalindrome = function () {
     return this.valueOf() === this.reverse().valueOf();
   };
   String.prototype.reverse = function () {
     return Array.prototype.slice.apply(this).reverse().join('');
   };
   let result = 0;
   for (let i = 999; i > 0; i--) {
     for (let j = i; j > 0; j--) {
   ...