Oracle SQL - Write SQL to list city whose Humidity is 89

Requirements

Here is the table

Demo

SQL>
SQL> drop table Report;

Table dropped.-- from  w w w  .j a  v a  2  s.  com

SQL> create table Report (
  2  City         VARCHAR2(11),
  3  Temperature  NUMBER,
  4  Humidity     NUMBER,
  5  Condition    VARCHAR2(9)
  6  );
SQL>
SQL> insert into Report values ('BOOK2S.COM',89,98,'CLEAR');
SQL> insert into Report values ('ROME',45,79,'RAIN');
SQL> insert into Report values ('PARIS',81,62,'CLOUDY');
SQL> insert into Report values ('MANCHESTER',66,98,'FOG');
SQL> insert into Report values ('ATHENS',97,89,'SUNNY');
SQL> insert into Report values ('CHICAGO',66,88,'RAIN');
SQL> insert into Report values ('SYDNEY',69,99,'SUNNY');
SQL> insert into Report values ('SPARTA',74,63,'CLOUDY');
SQL> insert into Report values ('BEIJING',104,83,'SMOG');
SQL> insert into Report values ('NEW YORK',100,93,'SUNNY');
SQL>

Write SQL to list city whose Humidity is 89

Demo

SQL>
SQL> select City from Report where Humidity = 89 ;

CITY-- www  .  j  av  a2s  . c om
-----------
ATHENS
SQL>