C++ array search by find()

Description

C++ array search by find()

#include <iostream> 
#include <array> 
#include <vector> 
#include <ios> 


using namespace std; 

int main(int argc, char *argv [])
{   /*from w  w  w .ja  v  a 2s. com*/

        const unsigned int ARRAY_SIZE = 5; 

        using MyArray = std::array<int, ARRAY_SIZE>; 
        MyArray = { 0, 1, 2, 3, 4 }; 

        for (unsigned int i = 0; i < ARRAY_SIZE; ++i) 
        { 
                if (myArray[i] == 2) 
                { 
                        cout << "Found: " << myArray[i] 
                                << " at position: " << i << endl; 
                } 
        } 
  
        for (auto iter=myArray.begin(); iter!=myArray.end(); ++iter) 
        { 
                if (*iter == 2) 
                { 
                        cout << "Found: " << *iter << endl; 
                } 
        } 
  
        for (auto& number : myArray) 
        { 
                if (number == 2) 
                { 
                        cout << "Found : " << number << endl; 
                } 
        } 
  
        MyArray::iterator found = find(myArray.begin(), myArray.end(), 2); 
        if (found != myArray.end()) 
        { 
                cout << "Found : " << *found << endl; 
        } 
        return 0; 
}



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