Java Arithmetic Operator sum the digits in an integer

Question

We would like to write a program that reads an integer between 0 and 1000.

Add all the digits in the integer.

For example, if an integer is 932, the sum of all its digits is 14.

Hint

Use the % operator to extract digits

Use the / operator to remove the extracted digit.

For instance, 932 % 10 = 2 and 932 / 10 = 93. 

import java.util.Scanner;

public class Main {
  public static void main(String[] args) {
    Scanner input = new Scanner(System.in);   // Create new Scanner object

    // Prompt the user to enter a number between 0 and 1000.
    System.out.print("Enter a number between 0 and 1000: ");
    int number = input.nextInt();

    //your code here

    // Display results
    System.out.println("The sum of the digits is " + sum);
  }/*ww  w .  j  a  v a 2  s .c  o m*/
}



import java.util.Scanner;

public class Main {
  public static void main(String[] args) {
    Scanner input = new Scanner(System.in);   // Create new Scanner object

    // Prompt the user to enter a number between 0 and 1000.
    System.out.print("Enter a number between 0 and 1000: ");
    int number = input.nextInt();

    // Compute the sum of the digits in the integer.
    int lessThan10 = number % 10;   // Extract the digit less than 10
    number /= 10;             // Remove the extracted digit
    int tens = number % 10;       // Extract the digit between 10 to 99
    number /= 10;             // Remove the extracted digit
    int hundreds = number % 10;   // Extract the digit between 100 to 999
    number /= 10;             // Remove the extracted digit
    int sum = hundreds + tens + lessThan10; 

    // Display results
    System.out.println("The sum of the digits is " + sum);
  }
}



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