Java BigInteger multiply

Question

We would like to find the first ten square numbers that are greater than Long.MAX_VALUE.

A square number is a number in the form of n^2.

For example, 4, 9, and 16 are square numbers. 


import java.math.BigInteger;

public class Main {
  public static void main(String[] args) {
    // Create a BigInteger for Long's maximum value, and another for its sqrt
    BigInteger longMax = new BigInteger(String.valueOf(Long.MAX_VALUE));
    long m = (long)(Math.sqrt(Long.MAX_VALUE));
    BigInteger n = new BigInteger(String.valueOf(m));

    //your code here
  }/*  w w w  .  j a  v a  2s  .  c  o m*/
}





import java.math.BigInteger;

public class Main {
  public static void main(String[] args) {
    // Create a BigInteger for Long's maximum value, and another for its sqrt
    BigInteger longMax = new BigInteger(String.valueOf(Long.MAX_VALUE));
    long m = (long)(Math.sqrt(Long.MAX_VALUE));
    BigInteger n = new BigInteger(String.valueOf(m));

    // Starting at n, find the next 10 squares of n, ensuring that they exceed
    // longMax
    int count = 0;
    while (count < 10) {
      BigInteger square = n.multiply(n);
      if (square.compareTo(longMax) == 1) {
        System.out.println(square);
        count++;
      }
      n = n.add(BigInteger.ONE);
    }
  }
}



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