Java OCA OCP Practice Question 1465

Question

Consider the following program:

public class Main {
   public static void main(String[] args) {
      calculate(2);// w w w.ja  va  2 s.  co  m
   }

   public static void calculate(int x) {
      String val;
      switch (x) {
      case 2:
      default:
         val = "def";
      }
      System.out.println(val);
   }
}

What will happen if you try to compile and run the program?

Select 2 options

A. It will not compile saying that variable val may not have been initialized..
B. It will compile and print def
C. As such it will not compile but it will compile if calculate (2); is replaced by calculate (3);
D. It will compile for any int values in calculate (...);

Correct Options are  : B D

Note

When you try to access a local variable, the compiler makes sure that it is initialized in all the cases.

If it finds that there is a case in which it may not be initialized then it flags an error.

For example:

int i; 
if ( somecondition) 
   i = 20; 
int k = i;

If some condition returns false, then i remains uninitialized hence the compiler flags an error.

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Java OCA OCP Practice Question 1465

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Note

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