Java OCA OCP Practice Question 1523

Question

What will be the output of the following program? 

public class Main{ 
   public static void main (String args [] ){ 
      int i = 0 ; 
      boolean bool1 = true ; 
      boolean bool2 = false; 
      boolean bool  = false; 
      bool =  ( bool2 &  m (i++) ); //1 
      bool =  ( bool2 && m (i++) ); //2 
      bool =  ( bool1  |  m (i++) ); //3 
      bool =  ( bool1  || m (i++) ); //4 
      System.out.println (i); /*from  ww w . ja v a 2s. c  o m*/
    } 
   public static boolean m (int i){ 
       return i>0 ? true  : false; 
    } 
}

Select 1 option

  • A. It will print 1.
  • B. It will print 2.
  • C. It will print 3.
  • D. It will print 4.
  • E. It will print 0. 


Correct Option is  : B

Note

& and | do not short circuit the expression but && and || do.

As the value of all the expressions ( 1 through 4) can be determined just by looking at the first part, && and || do not evaluate the rest of the expression, so method 1() is not called for 2 and 4.

Hence the value of i is incremented only twice.




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