Java OCA OCP Practice Question 2688

Question

Consider the following program and predict the output: 

import java.nio.file.*;

class Main {/* ww  w.j  ava  2 s  .  c om*/
   public static void main(String[] args) {
        // assume that the current directory is "D:\workspace\ch14-test"
        Path testFilePath = Paths.get(".\\Main");
        System.out.println("file name:" + testFilePath.getFileName());
        System.out.println("absolute path:" + testFilePath.toAbsolutePath());
        System.out.println("Normalized path:" + testFilePath.normalize());
   }
}

a)file name:Main//  w  ww  . j  av  a 2s .c  o m
  absolute path:D:\workspace\ch14-test\.\Main
  Normalized path:Main

b)file name:Main
  absolute path:D:\workspace\ch14-test\Main
  Normalized path:Main

c)file name:Main
  absolute path:D:\workspace\ch14-test\.\Main
  Normalized path:D:\workspace\ch14-test\.\Main

d)file name:Main
  absolute path:D:\workspace\ch14-test\.\Main
  Normalized path:D:\workspace\ch14-test\Main



a)

Note

The absolute path adds the path from the root directory;

however, it does not normalize the path.

Hence, " .\" will be retained in the resultant path. On the other hand, the normalize() method normalizes the path but does not make it absolute.




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