Java OCA OCP Practice Question 3077

Question

Assume that the current directory is "D:\workspace\ch14-test".

Choose the correct option based on this code segment: 

Path testFilePath = Paths.get(".\\Main");
System.out.println("file name:" + testFilePath.getFileName());
System.out.println("absolute path:" + testFilePath.toAbsolutePath());
System.out.println("Normalized path:" + testFilePath.normalize());

a)   file name:Main// w w  w  .  java 2  s .c  o  m

    absolute path:D:\workspace\ch14-test\.\Main
    Normalized path:Main

b)   file name:Main

    absolute path:D:\workspace\ch14-test\Main
    Normalized path:Main

c)   file name:Main

    absolute path:D:\workspace\ch14-test\.\Main
    Normalized path:D:\workspace\ch14-test\.\Main

d)   file name:Main

    absolute path:D:\workspace\ch14-test\.\Main
    Normalized path:D:\workspace\ch14-test\Main



a)

Note

the absolute path adds the path from the root directory; however, it does not normalize the path.

hence, " .\" will be retained in the resultant path.

the normalize() method normalizes the path but does not make it absolute.




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