Java while loop reverse an integer

Question

We would like to write a method with the following header to display an integer in reverse order: 

public static void reverse(int number)

For example, reverse(3456) displays 6543.

Write a test program that prompts the user to enter an integer and displays its reversal. 


import java.util.Scanner;

public class Main {
  public static void main(String[] args) {
    Scanner input = new Scanner(System.in); // Create Scanner

    System.out.println("Display and integer reversed:");
    System.out.print("Enter an integer: ");
    int number = input.nextInt();

    reverse(number);//from ww  w.j av a 2 s. c  om
  }

  /** Reverse Method displays an integer in reverse order */ 
  public static void reverse(int number) {
    //your code here
  }
}




import java.util.Scanner;

public class Main {
  public static void main(String[] args) {
    Scanner input = new Scanner(System.in); // Create Scanner

    System.out.println("Display and integer reversed:");
    System.out.print("Enter an integer: ");
    int number = input.nextInt();

    reverse(number);
  }

  /** Reverse Method displays an integer in reverse order */ 
  public static void reverse(int number) {
    while (number > 0) {
      System.out.print((number % 10));
      number /= 10;
    }
    System.out.println();
  }
}

Note

Another solution 

import java.util.Scanner;

public class Main {
  public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    System.out.print("Enter an integer: ");
    int entry = input.nextInt();

    reverse(entry);/*from  w w  w  .j  a va2  s  . c  o m*/
  }

  public static void reverse(int number) {
    StringBuilder s = new StringBuilder(number + "");
    System.out.println(s.reverse());
  }
}



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