Explicitly implement an interface member

/*
C#: The Complete Reference 
by Herbert Schildt 

Publisher: Osborne/McGraw-Hill (March 8, 2002)
ISBN: 0072134852
*/


// Explicitly implement an interface member. 
 
using System; 
 
interface IEven { 
  bool isOdd(int x); 
  bool isEven(int x); 
} 
 
class MyClass : IEven { 
  // explicit implementation 
  bool IEven.isOdd(int x) { 
    if((x%2) != 0) return true; 
    else return false; 
  } 
 
  // normal implementation 
  public bool isEven(int x) { 
    IEven o = this; // reference to invoking object 
 
    return !o.isOdd(x); 
  } 
} 
 
public class Demo { 
  public static void Main() { 
    MyClass ob = new MyClass(); 
    bool result; 
 
    result = ob.isEven(4); 
    if(result) Console.WriteLine("4 is even."); 
    else Console.WriteLine("3 is odd."); 
 
    // result = ob.isOdd(); // Error, not exposed 
  } 
}

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Explicitly implement an interface member : Interface « Class Interface « C# / C Sharp

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