Returns the filename for the specified URI. : URI « Network Protocol « Java

Returns the filename for the specified URI.

  Copyright 2009 Tomer Gabel <>

  Licensed under the Apache License, Version 2.0 (the "License");
  you may not use this file except in compliance with the License.
  You may obtain a copy of the License at

  Unless required by applicable law or agreed to in writing, software
  distributed under the License is distributed on an "AS IS" BASIS,
  See the License for the specific language governing permissions and
  limitations under the License.

  ant-intellij-tasks project (

  $Id: 106 2009-09-30 02:07:29Z tomergabel $

//package com.tomergabel.util;


 * A static container class for URI-related utility functions.
public final class UriUtils {
     * A static URI which, when resolved against another URI, returns the other URI's parent.
    private static final URI up = URI.create( ".." );

     * Returns the filename for the specified URI.
     * <p/>
     * For example, applyign this method to the URI &quot;<tt></tt>&quot; will
     * return &quot;<tt>article.html</tt>&quot;.
     * @param uri The URI for which to return the filename.
     * @return The filename of the resource represented by the specified URI.
     * @throws IllegalArgumentException <ul><li>The URI cannot be null.</li><li>A separator character could not be found
     *                                  in the specified URI.</li><li>The specified URI does not point to a file
     *                                  resource.</li></ul>
    public static String getFilename( final URI uri ) throws IllegalArgumentException {
        if ( uri == null )
            throw new IllegalArgumentException( "The URI cannot be null." );

        final String path = uri.getRawPath();
        final int finalSeparator = Math.max( path.lastIndexOf( '/' ), path.lastIndexOf( '\\' ) );
        if ( finalSeparator == -1 )
            throw new IllegalArgumentException( "A separator character could not found in the specified URI." );
        if ( finalSeparator == path.length() - 1 )
            throw new IllegalArgumentException( "The specified URI does not point to a file resource." );
        return path.substring( finalSeparator + 1 );


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