The simplest regular expression matches letters, letter for letter : REGEXP_INSTR « Regular Expressions « Oracle PL / SQL






The simplest regular expression matches letters, letter for letter

 


SQL> create table TestTable(
  2    ID                    VARCHAR2(4 BYTE)         NOT NULL,
  3    Description           VARCHAR2(40 BYTE)
  4  )
  5  /

Table created.

SQL>
SQL>
SQL> insert into TestTable (ID, Description) values('1','1234 5th Street');

1 row created.

SQL> insert into TestTable (ID, Description) values('2','1 Culloden Street');

1 row created.

SQL> insert into TestTable (ID, Description) values('3','1234 Road');

1 row created.

SQL> insert into TestTable (ID, Description) values('4','33 Thrid Road');

1 row created.

SQL> insert into TestTable (ID, Description) values('5','One than another');

1 row created.

SQL> insert into TestTable (ID, Description) values('6','2003 Movie');

1 row created.

SQL> insert into TestTable (ID, Description) values('7','Start With Letters');

1 row created.

SQL>
SQL> select * from TestTable;

ID   DESCRIPTION
---- ----------------------------------------
1    1234 5th Street
2    1 Culloden Street
3    1234 Road
4    33 Thrid Road
5    One than another
6    2003 Movie
7    Start With Letters

7 rows selected.

SQL>
SQL>
SQL>
SQL> -- The simplest regular expression matches letters, letter for letter
SQL>
SQL> SELECT REGEXP_INSTR(Description,'Road') One FROM testtable WHERE REGEXP_INSTR(Description,'Road') > 0;

       ONE
----------
         6
        10

SQL>
SQL>
SQL> drop table TestTable;

Table dropped.

SQL>
SQL>
           
         
  








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