Table join with data returned from function : Table Join « Table Joins « SQL Server / T-SQL






Table join with data returned from function

28> create table employee(
29>     ID          int,
30>     name        nvarchar (10),
31>     salary      int )
32> GO
1>
2> create table job(
3>     ID              int,
4>     title nvarchar  (10),
5>     averageSalary   int)
6> GO
1>
2>
3> insert into employee (ID, name, salary) values (1,  'Jason', 1234)
4> GO
1> insert into employee (ID, name, salary) values (2,  'Robert', 4321)
2> GO
1> insert into employee (ID, name, salary) values (3,  'Celia', 5432)
2> GO
1> insert into employee (ID, name, salary) values (4,  'Linda', 3456)
2> GO
1> insert into employee (ID, name, salary) values (5,  'David', 7654)
2> GO
1> insert into employee (ID, name, salary) values (6,  'James', 4567)
2> GO
1> insert into employee (ID, name, salary) values (7,  'Alison', 8744)
2> GO
1> insert into employee (ID, name, salary) values (8,  'Chris', 9875)
2> GO
1> insert into employee (ID, name, salary) values (9,  'Mary', 2345)
2> GO
1>
2> insert into job(ID, title, averageSalary) values(1,'Developer',3000)
3> GO
1> insert into job(ID, title, averageSalary) values(2,'Tester', 4000)
2> GO
1> insert into job(ID, title, averageSalary) values(3,'Designer', 5000)
2> GO
1> insert into job(ID, title, averageSalary) values(4,'Programmer', 6000)
2> GO
1>
2>
3> select * from employee;
4> GO
ID          name       salary
----------- ---------- -----------
          1 Jason             1234
          2 Robert            4321
          3 Celia             5432
          4 Linda             3456
          5 David             7654
          6 James             4567
          7 Alison            8744
          8 Chris             9875
          9 Mary              2345
1> select * from job;
2> GO
ID          title      averageSalary
----------- ---------- -------------
          1 Developer           3000
          2 Tester              4000
          3 Designer            5000
          4 Programmer          6000
1>
2> CREATE FUNCTION dbo.fnSalaryCount(@SalaryQty bigint)
3> RETURNS TABLE
4> AS
5> RETURN (SELECT *
6>         FROM Employee where
7>         salary > @SalaryQty
8>         )
9> GO
1>
2>
3>
4> SELECT DISTINCT name
5> FROM dbo.fnSalaryCount(25) AS a
6> JOIN job AS j
7>   ON a.id = j.id
8> GO
name
----------
Celia
Jason
Linda
Robert
1>
2> drop function fnSalaryCount
3> drop table employee;
4> drop table job;
5> GO
1>
2>

           
       








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