December 25, 1960 in German : format date « XSLT stylesheet « XML






  1. XML
  2. XSLT stylesheet
  3. format date

December 25, 1960 in German


File: Data.xml


File: Transform.xslt

<?xml version="1.0" encoding="utf-8"?>
<xsl:stylesheet version="2.0"
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
  xmlns:xs="http://www.w3.org/2001/XMLSchema">

  <xsl:output method="text"/>

  <xsl:template match="/">
    
    <xsl:text>December 25, 1960 in German: </xsl:text>
    <xsl:value-of select="format-date(xs:date('1960-12-25'), '[D] [MNn,3-3] [Y0001]', 'de', 'AD', 'DE')"/>

  </xsl:template>

</xsl:stylesheet>

Output:

December 25, 1960 in German: 25 Dez 1960








Related examples in the same category

1.format-date(/orgchart/@date, '[D1] [MNn] [Y1]')
2.select="format-date(current-date(),'[dwo]')"