subsequence and reverse : reverse « XSLT stylesheet « XML






subsequence and reverse




File: Data.xml
<?xml version="1.0" encoding="utf-8"?>
<favorite-books>
  <booklist>
    <book isbn="1111111111" 
      favorite="f1">XSLT</book>
    <book isbn="2222222222" 
      favorite="A">Java</book>
    <book isbn="3333333333" 
      favorite="A">C++</book>
    <book isbn="4444444444" 
      favorite="f1">SQL</book>
    <book isbn="5555555555" 
      favorite="B">Oracle</book>
    <book isbn="0375724443" 
      favorite="B">XML</book>
  </booklist>
</favorite-books>


File: Transform.xslt


<?xml version="1.0"?>
<xsl:stylesheet version="2.0" 
  xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
  
  <xsl:output method="text"/>
 
  <xsl:variable name="A-List" as="node()*">
    <xsl:sequence 
      select="/favorite-books/booklist
              /book[contains(@favorite, 'A')]"/>
  </xsl:variable>

  <xsl:variable name="B-List" as="node()*">
    <xsl:sequence 
      select="/favorite-books/booklist
              /book[contains(@favorite, 'B')]"/>
  </xsl:variable>

  <xsl:template match="/">
    <xsl:value-of 
      select="if (subsequence($A-List, 1, 1) is 
                  subsequence($B-List, 1, 1))
              then '    The first nodes are the same!&#xA;'
              else '    The first nodes aren''t the same!&#xA;'"/>
    
    <xsl:value-of 
      select="if (subsequence($A-List, 1, 1) is
                  subsequence(reverse($B-List), 1, 1))
              then '    The first nodes are the same!&#xA;'
              else '    The first nodes aren''t the same!&#xA;'"/>
  </xsl:template>

</xsl:stylesheet>

Output:

    The first nodes aren't the same!
    The first nodes aren't the same!

 








Related examples in the same category