literal « Integer « Java Data Type Q&A

1. Letters within integers. What are they? stackoverflow.com

This is an excerpt of code from a class I am working with in Java (below). Obviously the code is defining a static variable named EPSILON with the data type double. ...

2. why many programmers use integer literal on left handside of equality operator? stackoverflow.com

Possible Duplicates:
How to check for equals? (0 == i) or (i == 0)
Putting constants on the left side in comparisons?

Hi, Many a ...

3. Integer arithmetic in Java with char and integer literal stackoverflow.com

Can someone explain to me why the following code compiles OK in Java?

char c = 'a' + 10;

Why is this not equivalent to the following, which does not compile? ...

4. The literal of int xxxxx is out of range stackoverflow.com

I am slightly puzzled as I am working with data types at the moment in Java, and if I have understood correctly the type long accepts a value between the ranges ...

5. Why is 08 not a valid integer literal in Java? stackoverflow.com

Why is 08 considered an out of range int but 07 and below are not?

6. Any idea why I need to cast an integer literal to (int) here? stackoverflow.com

In the following example

int i = -128;
Integer i2 = (Integer) i; // compiles

Integer i3 = (Integer) -128; /*** Doesn't compile ***/

Integer i4 = (Integer) (int) -128; // compiles
Integer i4 = -128; ...

7. Integer literal coderanch.com

As an instance variable, int i is initialized to zero. The method that alters this value is never called. Instead, the overridden version of this method is called. Try this: abstract class Demo{ int i; protected void vv(){ i = 2147483647; i += 2; } } class DemoX extends Demo{ public void vv(){ [B]super.vv(); //calls superclass version[/B] System.out.println("Value: " + i); ...

8. integer literals coderanch.com

9. Character Wrapper and Literal int Assignment coderanch.com

Hi all, I've a two part question today: First: As a Character object can only be constructed using a char value, is the assignment of a literal int ... Character c1 = 65; ... replaced with the creation of a char that is used to create the Character ... char c = 65; Character c1 = new Character(c); ... at compile ...

10. The Literal Octal 08 of type int is out of range coderanch.com

11. int length=343 is 343 an integer literal or decimal literal??? coderanch.com

12. Integer literals implicit casting coderanch.com

The range of a byte is up to 127 , so first statement works fine . in second statement you are adding two bytes , 200 , in this case and storing it again on byte type. what else would you expect ?? Can you figure out the solution ?? int b = a+a ; should work with out truncating any ...

13. The literal Octal 008 (digit 8) of type int is out of range : Help ERR forums.oracle.com

14. Need some explanition with hexadecimal int literals. forums.oracle.com

Just like with the base-10 numbers that you're used to, but don't even think about what you're doing. In base 10: 65 = (5 * 10^0) + (6 * 10^1) = 5 + 60 = 65 In base 8: 101 = (1 * 8^0) + (0 * 8^1) + (1 * 8^2) = 1 + 0 + 64 = 65. Given ...