Literal « byte « Java Data Type Q&A

1. Why are there no byte or short literals in Java?

I can create a literal long by appending an L to the value; why can't I create a literal short or byte in some similar way? Why do I need to ...

2. How do you specify a byte literal in Java?

suppose I have a method

void f(byte b);
how can I call it with a numeric argument without casting:
gives an error. any ideas

3. how can I assign -1 as Hex Literal to byte type var?

hi, I want to assigne -128 to the byte type ,I can do it in the following ways byte b1 = -128; //int but within byte range byte b2 = -0x80; // hexadecimal for -128 System.out.println("b1 ="+b1+" b2 ="+b2); output -128 -128 Now I want to assigne -1 in the same way byte b1 = -1; //int within byte range byte ...

4. byte literals

If the literal is in the range 0-255 (instead of -128-127 when the conversion from int literal to byte is automatic) you can subtract 256 to get the value you want. This is identical to casting to byte. (I'm referring to assignment conversion) [ January 22, 2006: Message edited by: Joni Salonen ]

5. Literal for byte and short

Hello, when specifying numbers, you can append an 'f' for floats, 'd' for doubles, 'l' for longs, but I wonder, why isn't there any such thing for byte and short? Because Java then assumes int, you can't make use of autoboxing when a method or constructor has a java.lang.Byte or java.lang.Short in its param list. Instead you have to code something ...

6. Numeric literals and BYTE

Are numeric literals really not automatically converted to byte, if a function expects a byte? It seems that I have to cast the '0' below to a byte, which I find quite incredible, is that true? public class Mine { public static void main(String[] args) { test((byte)0); } public static void test(byte t) { System.out.println(t); } } ---- If I don't ...