Use out for int type : Method Parameter « Class « C# / CSharp Tutorial






using System;

class MyClass
{
   public int Val = 20;                     
}

class MainClass
{
   static void MyMethod(out MyClass f1, out int f2)
   {
      f1 = new MyClass();                   
      f1.Val = 25;                          
      f2 = 15;                              
   }

   static void Main()
   {
      MyClass myObject = null;
      int intValue;

      MyMethod(out myObject, out intValue);             

      Console.WriteLine("After  -- myObject.Val: {0}, intValue: {1}", myObject.Val, intValue);
   }
}
After  -- myObject.Val: 25, intValue: 15








7.6.Method Parameter
7.6.1.How Arguments Are Passed
7.6.2.Parameter modifiers
7.6.3.Pass int value to a function
7.6.4.Use a parameter in a member function
7.6.5.A member function with two arguments
7.6.6.Pass int without 'out' and 'ref'
7.6.7.Pass integer by ref
7.6.8.ref parameters
7.6.9.Pass integer value by value
7.6.10.params int[] args
7.6.11.Use out for int type
7.6.12.Creating a method with a reference argument.
7.6.13.Variable arguments to a method in C#.
7.6.14.Method parameter hides the class member field
7.6.15.C# Parameter Modifiers
7.6.16.use of 'outer variable' in anonymous method