Show products that are more expensive than average : Single Row Subquery « Query Select « Oracle PL/SQL Tutorial






SQL>
SQL> CREATE TABLE product (
  2       product_name     VARCHAR2(25) PRIMARY KEY,
  3       product_price    NUMBER(4,2),
  4       quantity_on_hand NUMBER(5,0),
  5       last_stock_date  DATE
  6       );

Table created.

SQL>
SQL> INSERT INTO product VALUES ('Product 1', 99,  1,    '15-JAN-03');

1 row created.

SQL> INSERT INTO product VALUES ('Product 2', 75,  1000, '15-JAN-02');

1 row created.

SQL> INSERT INTO product VALUES ('Product 3', 50,  100,  '15-JAN-03');

1 row created.

SQL> INSERT INTO product VALUES ('Product 4', 25,  10000, null);

1 row created.

SQL> INSERT INTO product VALUES ('Product 5', 9.95,1234, '15-JAN-04');

1 row created.

SQL> INSERT INTO product VALUES ('Product 6', 45,  1,    TO_DATE('December 31, 2008, 11:30 P.M.','Month dd, YYYY, HH:MI P.M.'));

1 row created.

SQL>
SQL> SELECT * FROM product
  2  WHERE  product_price > (SELECT AVG(product_price) FROM product);

PRODUCT_NAME              PRODUCT_PRICE QUANTITY_ON_HAND LAST_STOC
------------------------- ------------- ---------------- ---------
Product 1                            99                1 15-JAN-03
Product 2                            75             1000 15-JAN-02

SQL>
SQL>
SQL> drop table product;

Table dropped.

SQL>








2.36.Single Row Subquery
2.36.1.Writing Single Row Subqueries
2.36.2.Show products that are more expensive than average
2.36.3.Using Single Row Operators
2.36.4.Subqueries in a HAVING Clause
2.36.5.Subqueries in a FROM Clause (Inline Views)
2.36.6.A Couple of Errors when using subqueries in a FROM Clause (Inline Views)
2.36.7.Subqueries May Not Contain an ORDER BY Clause
2.36.8.A query that returns a result based on 'other rows'
2.36.9.Use greater than in sub query( list all employees who is younger than No 7)
2.36.10.Return null from subquery
2.36.11.Not Equal subquery
2.36.12.Not IN subquery
2.36.13.Older than another employee
2.36.14.Earn more than any managers
2.36.15.Earn more money than all managers
2.36.16.Earn more than average
2.36.17.List all employees who are younger than Jane
2.36.18.Subqueries in the WHERE Clause: equals
2.36.19.Subqueries in the WHERE Clause: less than
2.36.20.Find all employees who are younger than employee whose id is 9999