substr(date value,8)+16 : SUBSTR « Character String Functions « Oracle PL/SQL Tutorial






  1. Oracle PL/SQL Tutorial
  2. Character String Functions
  3. SUBSTR
SQL> create table emp
  2  ( empno      NUMBER(4)    constraint E_PK primary key
  3  , ename      VARCHAR2(8)
  4  , init       VARCHAR2(5)
  5  , job        VARCHAR2(8)
  6  , mgr        NUMBER(4)
  7  , bdate      DATE
  8  , sal        NUMBER(6,2)
  9  , comm       NUMBER(6,2)
 10  , deptno     NUMBER(2)    default 10
 11  ) ;

Table created.

SQL> insert into emp values(1,'Tom','N',   'Coder', 13,date '1965-12-17',  800 , NULL,  20);

1 row created.

SQL> insert into emp values(2,'Jack','JAM', 'Tester',6,date '1961-02-20',  1600, 300,   30);

1 row created.

SQL> insert into emp values(3,'Wil','TF' ,  'Tester',6,date '1962-02-22',  1250, 500,   30);

1 row created.

SQL> insert into emp values(4,'Jane','JM',  'Designer', 9,date '1967-04-02',  2975, NULL,  20);

1 row created.

SQL> insert into emp values(5,'Mary','P',  'Tester',6,date '1956-09-28',  1250, 1400,  30);

1 row created.

SQL> insert into emp values(6,'Black','R',   'Designer', 9,date '1963-11-01',  2850, NULL,  30);

1 row created.

SQL> insert into emp values(7,'Chris','AB',  'Designer', 9,date '1965-06-09',  2450, NULL,  10);

1 row created.

SQL> insert into emp values(8,'Smart','SCJ', 'Coder', 4,date '1959-11-26',  3000, NULL,  20);

1 row created.

SQL> insert into emp values(9,'Peter','CC',   'Designer',NULL,date '1952-11-17',  5000, NULL,  10);

1 row created.

SQL> insert into emp values(10,'Take','JJ', 'Tester',6,date '1968-09-28',  1500, 0,     30);

1 row created.

SQL> insert into emp values(11,'Ana','AA',  'Coder', 8,date '1966-12-30',  1100, NULL,  20);

1 row created.

SQL> insert into emp values(12,'Jane','R',   'Manager',   6,date '1969-12-03',  800 , NULL,  30);

1 row created.

SQL> insert into emp values(13,'Fake','MG',   'Coder', 4,date '1959-02-13',  3000, NULL,  20);

1 row created.

SQL> insert into emp values(14,'Mike','TJA','Manager',   7,date '1962-01-23',  1300, NULL,  10);

1 row created.

SQL>
SQL> select ename, substr(bdate,8)+16
  2  from   emp
  3  where  deptno = 10;

ENAME    SUBSTR(BDATE,8)+16
-------- ------------------
Chris                   981
Peter                   968
Mike                    978

SQL>
SQL> drop table emp;

Table dropped.








11.18.SUBSTR
11.18.1.The SUBSTR Function
11.18.2.substr(,) and substr(,,)
11.18.3.SUBSTR(x, start [, length]) returns a substring of x that begins at the position specified by start.
11.18.4.Substr retrieves a portion of the string
11.18.5.Retrieval begins at position 5 and again goes for 12 characters
11.18.6.A retrieval with no third argument: it starts at begin and retrieves the rest of the string
11.18.7.If begin is negative, then retrieval occurs from the right-hand side of original string
11.18.8.SUBSTR and INSTR used together
11.18.9.Combine SUBSTR and INSTR to deal with a table column
11.18.10.Combine DECODE and SUBSTR together
11.18.11.Example SELECT output using SUBSTR().
11.18.12.substr birthday
11.18.13.Compare substring in where statement
11.18.14.Manipulating Strings: SUBSTR and concatenation
11.18.15.substr(date value,8)+16